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Frequently Asked Questions (FAQ)
What are the solutions to the equation 2y^2+17y+45=(y+7)^2 ?
- The solutions to the equation 2y^2+17y+45=(y+7)^2 are y=1,y=-4
Find the zeros of 2y^2+17y+45=(y+7)^2
- The zeros of 2y^2+17y+45=(y+7)^2 are y=1,y=-4