What is the y=((sqrt(m)+2))/((m-3)*x-5m+7) ?

The y=((sqrt(m)+2))/((m-3)*x-5m+7) is

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y=((sqrt(m)+2))/((m-3)*x-5m+7)

y = \frac{( m + 2 )}{( m - 3 ) \cdot x - 5 m + 7}

Domain : m \geq 0

Y Intercepts : (0, \frac{m + 2}{- 5 m + 7})

Asymptotes : Vertical x = \frac{5 m - 7}{m - 3}, Horizontal y = 0

Extreme Points : {0 \leq m < \frac{7}{5} : Minimum (0, \frac{m + 2}{- 5 m + 7}), \frac{7}{5} < m < 3 or m > 3 : Maximum (0, \frac{m + 2}{- 5 m + 7})}

Solution steps

Domain of

\frac{m + 2}{( m - 3 ) \cdot x - 5 m + 7} : m \geq 0

Axis interception points of

\frac{m + 2}{( m - 3 ) \cdot x - 5 m + 7} :

Y Intercepts

: (0, \frac{m + 2}{- 5 m + 7})

Asymptotes of

\frac{m + 2}{( m - 3 ) \cdot x - 5 m + 7} :

Vertical

: x = \frac{5 m - 7}{m - 3},

Horizontal

: y = 0

Extreme Points of

\frac{m + 2}{( m - 3 ) \cdot x - 5 m + 7} : {0 \leq m < \frac{7}{5} : Minimum (0, \frac{m + 2}{- 5 m + 7}), \frac{7}{5} < m < 3 or m > 3 : Maximum (0, \frac{m + 2}{- 5 m + 7})}

y = (3 e^{x} + x) \cdot cos (x)

f (x) = 1 + 64 x^{2}

y = x^{2} - 2 x - 80

f (x) = \frac{lo g _{10} ( x )}{( x - 1 )}

f (x) = - x^{2} + 9 x + 12

What is the y=((sqrt(m)+2))/((m-3)*x-5m+7) ?
The y=((sqrt(m)+2))/((m-3)*x-5m+7) is