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Popular >

f(x)=2x^2+x+8

Solution

f (x) = 2 x^{2} + x + 8

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq \frac{63}{8}

Y Intercepts : (0, 8)

Vertex : Minimum (- \frac{1}{4}, \frac{63}{8})

Inverse : \frac{- 1 + 8 x - 63}{4}, \frac{- 1 - 8 x - 63}{4}

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Solution steps

Domain of

2 x^{2} + x + 8 : - \infty < x < \infty

Range of

2 x^{2} + x + 8 : f (x) \geq \frac{63}{8}

Axis interception points of

2 x^{2} + x + 8 :

Y Intercepts

: (0, 8)

Vertex of

2 x^{2} + x + 8 :

Minimum

(- \frac{1}{4}, \frac{63}{8})

Inverse of

2 x^{2} + x + 8 : \frac{- 1 + 8 x - 63}{4}, \frac{- 1 - 8 x - 63}{4}

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Frequently Asked Questions (FAQ)

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