en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(j)= 1/((0.02+j^{0.2))}

Solution

f (j) = \frac{1}{( 0.02 + j ^{0.2} )}

Solution

Domain : j < - 0.0000000032 or j > - 0.0000000032

Range : f (x) < 0 or f (x) > 0

Intercepts : None

Asymptotes : Vertical j = - 0.0000000032, Horizontal y = 0

Extreme Points : None

+1

Solution steps

Domain of

\frac{1}{0.02 + j ^{0.2}} : j < - 0.0000000032 or j > - 0.0000000032

Range of

\frac{1}{0.02 + j ^{0.2}} : f (x) < 0 or f (x) > 0

Axis interception points of

\frac{1}{0.02 + j ^{0.2}} :

None

Asymptotes of

\frac{1}{0.02 + j ^{0.2}} :

Vertical

: j = - 0.0000000032,

Horizontal

: y = 0

Extreme Points of

\frac{1}{0.02 + j ^{0.2}} :

None

Popular Examples

p (x) = x + 1

k(x)=((1+sin(x)))/n

k (x) = \frac{( 1 + sin ( x ) )}{n}

y=x^3-25x^2+158x-224

y = x^{3} - 25 x^{2} + 158 x - 224

f(x)=x^3-4x^2+6x-5

f (x) = x^{3} - 4 x^{2} + 6 x - 5

q(x)=x^3-x^2-x+1

q (x) = x^{3} - x^{2} - x + 1

Frequently Asked Questions (FAQ)

What is the f(j)= 1/((0.02+j^{0.2))} ?
The f(j)= 1/((0.02+j^{0.2))} is