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Popular >

p(x)=2x^2+4x-16

Solution

p (x) = 2 x^{2} + 4 x - 16

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - 18

X Intercepts : (2, 0), (- 4, 0), Y Intercepts : (0, - 16)

Vertex : Minimum (- 1, - 18)

Inverse : \frac{- 4 + 8 x + 144}{4}, \frac{- 4 - 8 x + 144}{4}

+1

Solution steps

Domain of

2 x^{2} + 4 x - 16 : - \infty < x < \infty

Range of

2 x^{2} + 4 x - 16 : f (x) \geq - 18

Axis interception points of

2 x^{2} + 4 x - 16 :

X Intercepts

: (2, 0), (- 4, 0),

Y Intercepts

: (0, - 16)

Vertex of

2 x^{2} + 4 x - 16 :

Minimum

(- 1, - 18)

Inverse of

2 x^{2} + 4 x - 16 : \frac{- 4 + 8 x + 144}{4}, \frac{- 4 - 8 x + 144}{4}

Popular Examples

f(x)=x^3-13x-10

f (x) = x^{3} - 13 x - 10

f(x)=4x^2+100x-60

f (x) = 4 x^{2} + 100 x - 60

parity f(x)=sqrt(cos(x))*cos(300*x)+sqrt(|x|)-9.3*(4-x^2)^{0.01}parity

f (x) = cos (x) \cdot cos (300 \cdot x) + ∣ x ∣ - 9.3 \cdot (4 - x^{2})^{0.01}

f(x)=x^3+2x^2-19x-20

f (x) = x^{3} + 2 x^{2} - 19 x - 20

p (x) = 1 - 1

Frequently Asked Questions (FAQ)

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