What is the asymptotes of f(x)=((x^2-4x))/(x^3-16x) ?

The asymptotes of f(x)=((x^2-4x))/(x^3-16x) is Vertical: x=-4,Horizontal: y=0

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asymptotes of f(x)=((x^2-4x))/(x^3-16x)

asymptotes

f (x) = \frac{( x ^{2} - 4 x )}{x ^{3} - 16 x}

Vertical : x = - 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4 x}{x ^{3} - 16 x} : x = - 4

Horizontal Asymptotes of

\frac{x ^{2} - 4 x}{x ^{3} - 16 x} : y = 0

Slant Asymptotes of

\frac{x ^{2} - 4 x}{x ^{3} - 16 x} :

None

Vertical : x = - 4, Horizontal : y = 0

\frac{( x ^{2} + 1 ) x - 2}{x - 2}

\frac{2 + x ^{2}}{1 - x ^{2}}

f (x) = \frac{x ^{2} + x}{x + 3}

\frac{1}{x - 8} + 9

\frac{4 x}{x ^{2} - 9}

What is the asymptotes of f(x)=((x^2-4x))/(x^3-16x) ?
The asymptotes of f(x)=((x^2-4x))/(x^3-16x) is Vertical: x=-4,Horizontal: y=0