What is the asymptotes of f(x)=(x^2-x-6)/(x^2-9) ?

The asymptotes of f(x)=(x^2-x-6)/(x^2-9) is Vertical: x=-3,Horizontal: y=1

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asymptotes of f(x)=(x^2-x-6)/(x^2-9)

asymptotes

f (x) = \frac{x ^{2} - x - 6}{x ^{2} - 9}

Vertical : x = - 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - x - 6}{x ^{2} - 9} : x = - 3

Horizontal Asymptotes of

\frac{x ^{2} - x - 6}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{x ^{2} - x - 6}{x ^{2} - 9} :

None

Vertical : x = - 3, Horizontal : y = 1

f (x) = \frac{( x ^{2} + 2 x - 1 )}{x}

y = \frac{1}{x - 1} + 2

\frac{6 x}{x - 2}

y = \frac{x ^{2} - 3 x + 4}{x - 2}

f (x) = \frac{3 x ^{2}}{5 x}

What is the asymptotes of f(x)=(x^2-x-6)/(x^2-9) ?
The asymptotes of f(x)=(x^2-x-6)/(x^2-9) is Vertical: x=-3,Horizontal: y=1