What is the asymptotes of 6/(x^2-9) ?

The asymptotes of 6/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0

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asymptotes of 6/(x^2-9)

asymptotes

\frac{6}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{6}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{6}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{6}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

\frac{( x ^{3} - 9 )}{( 3 x ^{4} + 5 )}

f (x) = - 5.5

f (x) = x^{2} - 3 x - 4

\frac{- x ^{2} - 2 x + 3}{x - 2}

f (x) = \frac{3 x ^{2} + 1}{x}

What is the asymptotes of 6/(x^2-9) ?
The asymptotes of 6/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0