What is the asymptotes of f(x)=(2x^2-2x+5)/(2x^2+2x) ?

The asymptotes of f(x)=(2x^2-2x+5)/(2x^2+2x) is Vertical: x=-1,x=0,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(2x^2-2x+5)/(2x^2+2x)

asymptotes

f (x) = \frac{2 x ^{2} - 2 x + 5}{2 x ^{2} + 2 x}

Vertical : x = - 1, x = 0, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 2 x + 5}{2 x ^{2} + 2 x} : x = - 1, x = 0

Horizontal Asymptotes of

\frac{2 x ^{2} - 2 x + 5}{2 x ^{2} + 2 x} : y = 1

Slant Asymptotes of

\frac{2 x ^{2} - 2 x + 5}{2 x ^{2} + 2 x} :

None

Vertical : x = - 1, x = 0, Horizontal : y = 1

\frac{2 x ^{2} - x - 3}{x ^{2} - 4}

ln (1 + x)

3^{x} - 2

3^{x} - 4

f (x) = \frac{x}{x ( x - 2 )}

What is the asymptotes of f(x)=(2x^2-2x+5)/(2x^2+2x) ?
The asymptotes of f(x)=(2x^2-2x+5)/(2x^2+2x) is Vertical: x=-1,x=0,Horizontal: y=1