What is the asymptotes of f(x)=((x^2+1))/((x+1)) ?

The asymptotes of f(x)=((x^2+1))/((x+1)) is Vertical: x=-1,Slant: y=x-1

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asymptotes of f(x)=((x^2+1))/((x+1))

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{( x + 1 )}

Vertical : x = - 1, Slant : y = x - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 1}{x + 1} : y = x - 1

Vertical : x = - 1, Slant : y = x - 1

f (x) = \frac{2 x}{x ^{2} - x}

\frac{( 2 x ^{2} + 6 x )}{- 4 x ^{2} + 8 x}

f (x) = \frac{5 x}{2 + x}

\frac{x ^{3} - x}{x ^{2} - 4}

f (x) = \frac{8 x ^{2} + 18}{10 x ^{2} - 9}

What is the asymptotes of f(x)=((x^2+1))/((x+1)) ?
The asymptotes of f(x)=((x^2+1))/((x+1)) is Vertical: x=-1,Slant: y=x-1