What is the asymptotes of 4/((x^2-9)) ?

The asymptotes of 4/((x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=0

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asymptotes of 4/((x^2-9))

asymptotes

\frac{4}{( x ^{2} - 9 )}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{4}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{4}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{4}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

f (x) = (\frac{1}{3})^{x} - 2

3^{x} + 2

f (x) = \frac{x ^{2}}{x ^{3}}

- 10 (x + 9)^{4} (x - 4)^{4}

f (x) = \frac{e ^{- x}}{x + 1}

What is the asymptotes of 4/((x^2-9)) ?
The asymptotes of 4/((x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=0