What is the asymptotes of f(x)=(3x^2+1)/(2x-1) ?

The asymptotes of f(x)=(3x^2+1)/(2x-1) is Vertical: x= 1/2 ,Slant: y= 3/2 x+3/4

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asymptotes of f(x)=(3x^2+1)/(2x-1)

asymptotes

f (x) = \frac{3 x ^{2} + 1}{2 x - 1}

Vertical : x = \frac{1}{2}, Slant : y = \frac{3}{2} x + \frac{3}{4}

Solution steps

Vertical asymptotes of

\frac{3 x ^{2} + 1}{2 x - 1} : x = \frac{1}{2}

Horizontal Asymptotes of

\frac{3 x ^{2} + 1}{2 x - 1} :

None

Slant Asymptotes of

\frac{3 x ^{2} + 1}{2 x - 1} : y = \frac{3}{2} x + \frac{3}{4}

Vertical : x = \frac{1}{2}, Slant : y = \frac{3}{2} x + \frac{3}{4}

f (x) = arctan (- e^{4 x})

\frac{( x + 4 )}{x ^{2} + x - 12}

f (x) = \frac{2 x ^{2} + 5 x - 7}{x - 3}

f (x) = \frac{( 4 x + 1 )}{x + 2}

\frac{2 x + 1}{x ^{2}}

What is the asymptotes of f(x)=(3x^2+1)/(2x-1) ?
The asymptotes of f(x)=(3x^2+1)/(2x-1) is Vertical: x= 1/2 ,Slant: y= 3/2 x+3/4