What is the asymptotes of f(x)=(2x+6)/(x^2-9) ?

The asymptotes of f(x)=(2x+6)/(x^2-9) is Vertical: x=3,Horizontal: y=0

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asymptotes of f(x)=(2x+6)/(x^2-9)

asymptotes

f (x) = \frac{2 x + 6}{x ^{2} - 9}

Vertical : x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2 x + 6}{x ^{2} - 9} : x = 3

Horizontal Asymptotes of

\frac{2 x + 6}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{2 x + 6}{x ^{2} - 9} :

None

Vertical : x = 3, Horizontal : y = 0

f (x) = \frac{x + 2}{x - 5}

f (x) = \frac{( x ^{2} )}{( x - 1 ) ^{2}}

f (x) = \frac{- x - x ^{2}}{( x + 1 ) ( x - 2 )}

f (x) = \frac{- x ^{2}}{x ^{2} + 4 x - 5}

f (x) = \frac{12}{5 x + 20} + 3

What is the asymptotes of f(x)=(2x+6)/(x^2-9) ?
The asymptotes of f(x)=(2x+6)/(x^2-9) is Vertical: x=3,Horizontal: y=0