What is the asymptotes of f(x)=(x^2+2x+1)/(6x^2-x-7) ?

The asymptotes of f(x)=(x^2+2x+1)/(6x^2-x-7) is Vertical: x= 7/6 ,Horizontal: y= 1/6

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asymptotes of f(x)=(x^2+2x+1)/(6x^2-x-7)

asymptotes

f (x) = \frac{x ^{2} + 2 x + 1}{6 x ^{2} - x - 7}

Vertical : x = \frac{7}{6}, Horizontal : y = \frac{1}{6}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x + 1}{6 x ^{2} - x - 7} : x = \frac{7}{6}

Horizontal Asymptotes of

\frac{x ^{2} + 2 x + 1}{6 x ^{2} - x - 7} : y = \frac{1}{6}

Slant Asymptotes of

\frac{x ^{2} + 2 x + 1}{6 x ^{2} - x - 7} :

None

Vertical : x = \frac{7}{6}, Horizontal : y = \frac{1}{6}

f (x) = x 9 - x^{2}

- lo g_{3} (x)

f (x) = \frac{x ^{2} - 7 x + 6}{x ^{2} - 1}

f (x) = \frac{x - 2}{x ^{2} + 4 x - 5}

\frac{x - 3}{2 x + 7}

What is the asymptotes of f(x)=(x^2+2x+1)/(6x^2-x-7) ?
The asymptotes of f(x)=(x^2+2x+1)/(6x^2-x-7) is Vertical: x= 7/6 ,Horizontal: y= 1/6