What is the critical f(x)=x^{1/9}-x^{-8/9} ?

The critical f(x)=x^{1/9}-x^{-8/9} is x=-8

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critical f(x)=x^{1/9}-x^{-8/9}

critical points

f (x) = x^{\frac{1}{9}} - x^{- \frac{8}{9}}

x = - 8

Solution steps

x^{\frac{1}{9}} - x^{- \frac{8}{9}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 8, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{1}{9}} - x^{- \frac{8}{9}} : x < 0 or x > 0

x^{\frac{1}{9}} - x^{- \frac{8}{9}}

is not defined at

x = 0

, therefore:

x = - 8

f (x, y) = x^{4} + y^{4} - 2 x^{2} - 2 y^{2} + 4 x y

f (x) = x^{2} e^{17 x}

f (x) = x^{\frac{1}{2}} (x - 4)

f (x) = \frac{x ^{2} + 5 x + 4}{x ^{2}}

f (x) = x^{\frac{2}{5}} (x - 4)

What is the critical f(x)=x^{1/9}-x^{-8/9} ?
The critical f(x)=x^{1/9}-x^{-8/9} is x=-8