What is the critical (x^2)/(sqrt(x^2-1)) ?

The critical (x^2)/(sqrt(x^2-1)) is x=-sqrt(2),x=sqrt(2)

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critical (x^2)/(sqrt(x^2-1))

critical points

\frac{x ^{2}}{x ^{2} - 1}

x = - 2, x = 2

Solution steps

\frac{x ^{2}}{x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x ^{2} - 1} : x < - 1 or x > 1

\frac{x ^{2}}{x ^{2} - 1}

is not defined at

x = - 1, x = 1

, therefore:

x = - 2, x = 2

x^{4} - 8 x^{2} + 4

f (x) = - x^{3} + 2 x^{2}

f (x, y) = x y + 2 x

f (x) = \frac{1}{x - 2}

f (x) = x^{2} (3 x - 1)^{3}

What is the critical (x^2)/(sqrt(x^2-1)) ?
The critical (x^2)/(sqrt(x^2-1)) is x=-sqrt(2),x=sqrt(2)