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Frequently Asked Questions (FAQ)
What is the f(x,y)=-x^3-y^3+(3x^2)/3+3y^2 ?
- The f(x,y)=-x^3-y^3+(3x^2)/3+3y^2 is Minimum(0,0),Saddle(0,2),Saddle(2/3 ,0),Maximum(2/3 ,2)