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Popular >

extreme f(x)=x^4-3x^3+3x^2+1

Solution

extreme points

f (x) = x^{4} - 3 x^{3} + 3 x^{2} + 1

Solution

Minimum (0, 1)

Solution steps

f^{'} (x) = 4 x^{3} - 9 x^{2} + 6 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{4} - 3 x^{3} + 3 x^{2} + 1 : 1

Minimum (0, 1)

Popular Examples

extreme f(x)=(5x^2-x^4)/9 extreme points

f (x) = \frac{5 x ^{2} - x ^{4}}{9}

extreme f(x,y)=xy+2x+3y extreme points

f (x, y) = x y + 2 x + 3 y

extreme f(x)=(x^2-9)/(x^2+9)extreme points

f (x) = \frac{x ^{2} - 9}{x ^{2} + 9}

extreme f(x)=5-2x^2 extreme points

f (x) = 5 - 2 x^{2}

extreme f(x)=\sqrt[3]{x+4}extreme points

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4-3x^3+3x^2+1 ?
The extreme f(x)=x^4-3x^3+3x^2+1 is Minimum(0,1)