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Popular >

extreme f(x)=x^3-6x^2+12x+1

Solution

extreme points

f (x) = x^{3} - 6 x^{2} + 12 x + 1

Solution

Saddle (2, 9)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 12

Find intervals:

Increasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{3} - 6 x^{2} + 12 x + 1 : 9

Saddle (2, 9)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3-6x^2+12x+1 ?
The extreme f(x)=x^3-6x^2+12x+1 is Saddle(2,9)