What is the extreme x^2y+xy^2+3xy ?

The extreme x^2y+xy^2+3xy is Saddle(0,-3),Maximum(-1,-1)

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extreme x^2y+xy^2+3xy

extreme points

x^{2} y + x y^{2} + 3 x y

Saddle (0, - 3), Maximum (- 1, - 1)

Solution steps

Find the critical points:

(0, - 3), (- 1, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2 x

D (x, y) = - 4 x y - 4 x^{2} - 12 x - 4 y^{2} - 12 y - 9

Check the sign of at each critical point

Check critical point

(0, - 3) :

Saddle

Check critical point

(- 1, - 1) :

Maximum

Saddle (0, - 3), Maximum (- 1, - 1)

\frac{x ^{2} + 4 x + 3}{x ^{3} - 2 x ^{2} - 5 x + 6}

f (x, y) = 4 x^{3} + y^{3} - 12 x - 3 y

f (x, y) = x y - x^{2} y - x y^{2}

f (x) = 2 x^{2} - 4 x

f (x) = 12 x y - x^{3} - y^{3}

What is the extreme x^2y+xy^2+3xy ?
The extreme x^2y+xy^2+3xy is Saddle(0,-3),Maximum(-1,-1)