What is the extreme f(x)=(x^3)/3-x^2-3x+1 ?

The extreme f(x)=(x^3)/3-x^2-3x+1 is Maximum(-1, 8/3),Minimum(3,-8)

Popular >

extreme f(x)=(x^3)/3-x^2-3x+1

extreme points

f (x) = \frac{x ^{3}}{3} - x^{2} - 3 x + 1

Maximum (- 1, \frac{8}{3}), Minimum (3, - 8)

Solution steps

f^{'} (x) = x^{2} - 2 x - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

\frac{x ^{3}}{3} - x^{2} - 3 x + 1 : \frac{8}{3}

Maximum (- 1, \frac{8}{3})

Plug

x = 3

into

\frac{x ^{3}}{3} - x^{2} - 3 x + 1 : - 8

Minimum (3, - 8)

Maximum (- 1, \frac{8}{3}), Minimum (3, - 8)

f (x) = 4 x^{3} - 3 x^{2} - 6 x + 3, (0, 10)

x^{2} y + x y^{2} + 3 x y

\frac{x ^{2} + 4 x + 3}{x ^{3} - 2 x ^{2} - 5 x + 6}

f (x, y) = 4 x^{3} + y^{3} - 12 x - 3 y

f (x, y) = x y - x^{2} y - x y^{2}

What is the extreme f(x)=(x^3)/3-x^2-3x+1 ?
The extreme f(x)=(x^3)/3-x^2-3x+1 is Maximum(-1, 8/3),Minimum(3,-8)