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Popular >

extreme f(x)=x^2-12x+10

Solution

extreme points

f (x) = x^{2} - 12 x + 10

Solution

Minimum (6, - 26)

Solution steps

f^{'} (x) = 2 x - 12

Find intervals:

Decreasing

: - \infty < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 6

into

x^{2} - 12 x + 10 : - 26

Minimum (6, - 26)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-12x+10 ?
The extreme f(x)=x^2-12x+10 is Minimum(6,-26)