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Popular >

extreme f(x)=x^2+(16)/x

Solution

extreme points

f (x) = x^{2} + \frac{16}{x}

Solution

Minimum (2, 12)

Solution steps

f^{'} (x) = 2 x - \frac{16}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{2} + \frac{16}{x} : 12

Minimum (2, 12)

Graph

Popular Examples

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f (x) = 2 x^{3} + 3 x^{2} - 120 x, 0 \leq x \leq 5

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f (x) = - 2 x^{3} - 9 x^{2} + 24 x + 40

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+(16)/x ?
The extreme f(x)=x^2+(16)/x is Minimum(2,12)