What is the extreme f(x)=((x+2)^2)/(x-2) ?

The extreme f(x)=((x+2)^2)/(x-2) is Maximum(-2,0),Minimum(6,16)

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extreme f(x)=((x+2)^2)/(x-2)

extreme points

f (x) = \frac{( x + 2 ) ^{2}}{x - 2}

Maximum (- 2, 0), Minimum (6, 16)

Solution steps

f^{'} (x) = \frac{x ^{2} - 4 x - 12}{( x - 2 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Decreasing

: 2 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = - 2

into

\frac{( x + 2 ) ^{2}}{x - 2} : 0

Maximum (- 2, 0)

Plug

x = 6

into

\frac{( x + 2 ) ^{2}}{x - 2} : 16

Minimum (6, 16)

Maximum (- 2, 0), Minimum (6, 16)

y = 3 x^{4} + 4 x^{3}

f (x) = x^{4} - 4 x^{3} - 18 x^{2}

y = x^{4} - 2 x^{2}

f (x, y) = ln (x^{2} + y^{2} - 1)

f (x) = x^{2} - x - ln (x)

What is the extreme f(x)=((x+2)^2)/(x-2) ?
The extreme f(x)=((x+2)^2)/(x-2) is Maximum(-2,0),Minimum(6,16)