What is the domain of (x^2-1)/(x^2-2x-3) ?

The domain of (x^2-1)/(x^2-2x-3) is x 3

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domain of (x^2-1)/(x^2-2x-3)

domain

\frac{x ^{2} - 1}{x ^{2} - 2 x - 3}

x < - 1 or - 1 < x < 3 or x > 3

Solution steps

Find undefined (singularity) points:

x = 3, x = - 1

The function domain

x < - 1 or - 1 < x < 3 or x > 3

y = 2^{x} + 1

f (x) = \frac{x + 6}{x - 6}

f (x) = \frac{x ^{2} - 16}{x ^{2} + 49}

g (x) = x - 2

f (x) = lo g_{5} (4 - x) - 2

What is the domain of (x^2-1)/(x^2-2x-3) ?
The domain of (x^2-1)/(x^2-2x-3) is x<-1\lor-1<x<3\lor x>3