What is the domain of f(x)= x/(\sqrt[3]{x^2-1)} ?

The domain of f(x)= x/(\sqrt[3]{x^2-1)} is x 1

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domain of f(x)= x/(\sqrt[3]{x^2-1)}

domain

f (x) = \frac{x}{3 x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = 2 sin (2 x)

f (x) = x^{2} - 20 x + 104

2 x^{2} - 13 x - 7

f (x) = \frac{2 x + 2}{x ^{2} + 3 x - 40}

y = ∣ x + 3 ∣

What is the domain of f(x)= x/(\sqrt[3]{x^2-1)} ?
The domain of f(x)= x/(\sqrt[3]{x^2-1)} is x<-1\lor-1<x<1\lor x>1