What is the domain of f(x)=(sqrt(x+5))/((x+8)(x-9)) ?

The domain of f(x)=(sqrt(x+5))/((x+8)(x-9)) is -5 9

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domain of f(x)=(sqrt(x+5))/((x+8)(x-9))

domain

f (x) = \frac{x + 5}{( x + 8 ) ( x - 9 )}

- 5 \leq x < 9 or x > 9

Interval Notation

[- 5, 9) \cup (9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 5

Find undefined (singularity) points:

x = - 8, x = 9

Combine real regions and undefined points for final function domain

- 5 \leq x < 9 or x > 9

tan (2 t)

2 x^{2} - 12 x + 9

f (x) = ln (2 + ln (x))

f (x) = \frac{( x + 1 )}{x ^{2} - 1}

f (x) = \frac{3 x - 6}{x ^{2} - 6}

What is the domain of f(x)=(sqrt(x+5))/((x+8)(x-9)) ?
The domain of f(x)=(sqrt(x+5))/((x+8)(x-9)) is -5<= x<9\lor x>9