What is the domain of f(x)=sqrt((2x)/(x^2-4)) ?

The domain of f(x)=sqrt((2x)/(x^2-4)) is -2 2

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domain of f(x)=sqrt((2x)/(x^2-4))

domain

f (x) = \frac{2 x}{x ^{2} - 4}

- 2 < x \leq 0 or x > 2

Solution steps

Find non-negative values for radicals:

- 2 < x \leq 0 or x > 2

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

- 2 < x \leq 0 or x > 2

\frac{x ^{2} - 4}{x - 1}

f (x) = \frac{x ^{2} + 5}{x + 2}

f (x) = \frac{3 x}{8 - x}

\frac{e ^{2 x} - 1}{1 + e ^{2 x}}

3^{x} - 3

What is the domain of f(x)=sqrt((2x)/(x^2-4)) ?
The domain of f(x)=sqrt((2x)/(x^2-4)) is -2<x<= 0\lor x>2