What is the domain of f(x)=((2x^2-6x+4))/((-3x-5)) ?

The domain of f(x)=((2x^2-6x+4))/((-3x-5)) is x -5/3

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domain of f(x)=((2x^2-6x+4))/((-3x-5))

domain

f (x) = \frac{( 2 x ^{2} - 6 x + 4 )}{( - 3 x - 5 )}

x < - \frac{5}{3} or x > - \frac{5}{3}

Interval Notation

(- \infty, - \frac{5}{3}) \cup (- \frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{5}{3}

The function domain

x < - \frac{5}{3} or x > - \frac{5}{3}

4 cos (\frac{1}{x})

\frac{1}{x ^{2} - x - 6}

f (x) = \frac{x ^{2}}{4}

f (x) = \frac{1}{1.4 x - 9.3 x ^{2}}

f (x) = \frac{1}{4 x - 1}

What is the domain of f(x)=((2x^2-6x+4))/((-3x-5)) ?
The domain of f(x)=((2x^2-6x+4))/((-3x-5)) is x<-5/3 \lor x>-5/3