What is the domain of f(x)=(sqrt(2x+9))/(x^2) ?

The domain of f(x)=(sqrt(2x+9))/(x^2) is -9/2 0

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domain of f(x)=(sqrt(2x+9))/(x^2)

domain

f (x) = \frac{2 x + 9}{x ^{2}}

- \frac{9}{2} \leq x < 0 or x > 0

Solution steps

Find non-negative values for radicals:

x \geq - \frac{9}{2}

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- \frac{9}{2} \leq x < 0 or x > 0

f (x) = x^{2} - 25

y = 3

\frac{2 x ^{2} - 8}{x ^{2} + x - 2}

\frac{x ^{2} + 30 x - 99}{x - 3}

f (x) = e

What is the domain of f(x)=(sqrt(2x+9))/(x^2) ?
The domain of f(x)=(sqrt(2x+9))/(x^2) is -9/2 <= x<0\lor x>0