What is the inverse of f(x)=x+sqrt(x^2+1) ?

The inverse of f(x)=x+sqrt(x^2+1) is -(1-x^2)/(2x)

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inverse of f(x)=x+sqrt(x^2+1)

inverse

f (x) = x + x^{2} + 1

- \frac{1 - x ^{2}}{2 x}

Solution steps

y = x + x^{2} + 1

Replace

x

with

y

x = y + y^{2} + 1

Solve for

y, x = y + y^{2} + 1

- \frac{1 - x ^{2}}{2 x}

3 + 5 + 8 x

f (x) = 2 e^{2 x + 1} + 1

f (x) = 0.3

f (x) = \frac{1}{4} x + 6

f (x) = \frac{3 x - 4}{7}

What is the inverse of f(x)=x+sqrt(x^2+1) ?
The inverse of f(x)=x+sqrt(x^2+1) is -(1-x^2)/(2x)