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Frequently Asked Questions (FAQ)
What is the inverse of f(x)=log_{10}(-2x^2+8x-a) ?
- The inverse of f(x)=log_{10}(-2x^2+8x-a) is -(-8+sqrt(64+8(-a-10^x)))/4 ,-(-8-sqrt(64+8(-a-10^x)))/4