What is the asymptotes of (x^2-4x-5)/(2x^2-x-10) ?

The asymptotes of (x^2-4x-5)/(2x^2-x-10) is Vertical: x=-2,x= 5/2 ,Horizontal: y= 1/2

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asymptotes of (x^2-4x-5)/(2x^2-x-10)

asymptotes

\frac{x ^{2} - 4 x - 5}{2 x ^{2} - x - 10}

Vertical : x = - 2, x = \frac{5}{2}, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4 x - 5}{2 x ^{2} - x - 10} : x = - 2, x = \frac{5}{2}

Horizontal Asymptotes of

\frac{x ^{2} - 4 x - 5}{2 x ^{2} - x - 10} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} - 4 x - 5}{2 x ^{2} - x - 10} :

None

Vertical : x = - 2, x = \frac{5}{2}, Horizontal : y = \frac{1}{2}

\frac{2 x}{3 x - 1}

f (x) = 4 x^{2} - 3 x + 1

- x + 6

f (x) = x^{3} - 9 x^{2} + 2

y = 5^{x}

What is the asymptotes of (x^2-4x-5)/(2x^2-x-10) ?
The asymptotes of (x^2-4x-5)/(2x^2-x-10) is Vertical: x=-2,x= 5/2 ,Horizontal: y= 1/2