What is the inverse of f(x)=(-x+9)/(3+4x) ?

The inverse of f(x)=(-x+9)/(3+4x) is (9-3x)/(4x+1)

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inverse of f(x)=(-x+9)/(3+4x)

inverse

f (x) = \frac{- x + 9}{3 + 4 x}

\frac{9 - 3 x}{4 x + 1}

Solution steps

y = \frac{- x + 9}{3 + 4 x}

Replace

x

with

y

x = \frac{- y + 9}{3 + 4 y}

Solve for

y, x = \frac{- y + 9}{3 + 4 y}

\frac{9 - 3 x}{4 x + 1}

(6, - 3), (8, 8)

f (x) = x^{3} + 2 x^{2} - 9 x - 18

f (x) = 3 (x - 2)

f (x) = - 4^{(x - 3)} + 3

- 7 x - 5 y = 5

What is the inverse of f(x)=(-x+9)/(3+4x) ?
The inverse of f(x)=(-x+9)/(3+4x) is (9-3x)/(4x+1)