What is the domain of x/(2x-sqrt(x^2-2x)) ?

The domain of x/(2x-sqrt(x^2-2x)) is x = 2

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domain of x/(2x-sqrt(x^2-2x))

domain

\frac{x}{2 x - x ^{2} - 2 x}

x < 0 or x \geq 2

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 2

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x < 0 or x \geq 2

f (x) = lo g_{2} (8 x)

f (x) = \frac{2 x + 5}{x - 3}

y = - \frac{5}{6} x - 5, (- 8, 9)

f (x) = \frac{\frac{5}{x}}{\frac{5}{x} + 5}

What is the domain of x/(2x-sqrt(x^2-2x)) ?
The domain of x/(2x-sqrt(x^2-2x)) is x<0\lor x>= 2