What is the inverse of f(x)=2(x-3)^2+6 ?

The inverse of f(x)=2(x-3)^2+6 is sqrt((x-6)/2)+3,-sqrt((x-6)/2)+3

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inverse of f(x)=2(x-3)^2+6

inverse

f (x) = 2 (x - 3)^{2} + 6

\frac{x - 6}{2} + 3, - \frac{x - 6}{2} + 3

Solution steps

y = 2 (x - 3)^{2} + 6

Replace

x

with

y

x = 2 (y - 3)^{2} + 6

Solve for

y, x = 2 (y - 3)^{2} + 6

\frac{x - 6}{2} + 3, - \frac{x - 6}{2} + 3

(0, - 2), (3, - 3)

2 x + 5 y + 2 = 0

f (x) = \frac{2 x - 1}{x ^{2} - 6 x + 5}

f (x) = lo g_{3} (x + 3)

\frac{x}{2 x - x ^{2} - 2 x}

What is the inverse of f(x)=2(x-3)^2+6 ?
The inverse of f(x)=2(x-3)^2+6 is sqrt((x-6)/2)+3,-sqrt((x-6)/2)+3