What is the inverse of f(x)=(x-1)/(2x+1) ?

The inverse of f(x)=(x-1)/(2x+1) is (-1-x)/(2x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x-1)/(2x+1)

inverse

f (x) = \frac{x - 1}{2 x + 1}

\frac{- 1 - x}{2 x - 1}

Solution steps

y = \frac{x - 1}{2 x + 1}

Replace

x

with

y

x = \frac{y - 1}{2 y + 1}

Solve for

y, x = \frac{y - 1}{2 y + 1}

\frac{- 1 - x}{2 x - 1}

f (x) = 105 - 20 sin (\frac{5 π}{4} x)

3 x - 2 y = 6

36 - x^{2}

f (x) = 9 + (8 + x)^{\frac{1}{2}}

f (x) = 3 x^{2} + x - 2

What is the inverse of f(x)=(x-1)/(2x+1) ?
The inverse of f(x)=(x-1)/(2x+1) is (-1-x)/(2x-1)