en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (-3,-1),(9,2)

Solution

midpoint

(- 3, - 1), (9, 2)

Solution

(3, \frac{1}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 3, - 1), (x_{2}, y_{2}) = (9, 2)

= (\frac{9 - 3}{2}, \frac{2 - 1}{2})

Refine

= (3, \frac{1}{2})

Popular Examples

range of sqrt(x^2-2x+5)range

x^{2} - 2 x + 5

x = 5

extreme f(x)=-6/(x-7)extreme points

f (x) = - \frac{6}{x - 7}

amplitude of y= 1/2 cos(3x+pi)-5 amplitude

y = \frac{1}{2} cos (3 x + π) - 5

domain of f(x)=(x^2+20x+1)/(x^2+2x+1)domain

f (x) = \frac{x ^{2} + 20 x + 1}{x ^{2} + 2 x + 1}

Frequently Asked Questions (FAQ)

What is the midpoint (-3,-1),(9,2) ?
The midpoint (-3,-1),(9,2) is (3, 1/2)