What is the range of (8x-8)/(x+2) ?

The range of (8x-8)/(x+2) is f(x) 8

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range of (8x-8)/(x+2)

range

\frac{8 x - 8}{x + 2}

f (x) < 8 or f (x) > 8

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{8 x - 8}{x + 2}

Inverse of

\frac{8 x - 8}{x + 2} : \frac{- 8 - 2 x}{x - 8}

\frac{- 8 - 2 x}{x - 8}

Find the domain of each inverse function

Domain of

\frac{- 8 - 2 x}{x - 8} : x < 8 or x > 8

Combine the intervals

f (x) < 8 or f (x) > 8

f (x) = \frac{1}{x + 3} - 4

h (x) = \frac{- 5 x ^{3}}{9 x ^{2} - 4}

f (x) = \frac{x + 4}{x - 6}

9 = 3 y - 6 x, (4, - 8)

What is the range of (8x-8)/(x+2) ?
The range of (8x-8)/(x+2) is f(x)<8\lor f(x)>8