What is the critical f(x)=-x^{2/3}(x-2) ?

The critical f(x)=-x^{2/3}(x-2) is x=0,x= 4/5

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critical f(x)=-x^{2/3}(x-2)

critical points

f (x) = - x^{\frac{2}{3}} (x - 2)

x = 0, x = \frac{4}{5}

Solution steps

- x^{\frac{2}{3}} (x - 2)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{4}{5}, x = 0

Identify critical points not in

f (x)

domain

Domain of

- x^{\frac{2}{3}} (x - 2) : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{4}{5}

f (x) = \frac{( 1 - e ^{- x} )}{1 + e ^{- x}}

f (x) = 4 x

f (x) = - 4 sin (2 x - 7) + 3

f (x) = x^{3} - 3 x^{2} - x + 1

f (x) = 9 - x^{2}

What is the critical f(x)=-x^{2/3}(x-2) ?
The critical f(x)=-x^{2/3}(x-2) is x=0,x= 4/5