What is the domain of f(x)= 1/(x^2-x-2) ?

The domain of f(x)= 1/(x^2-x-2) is x 2

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domain of f(x)= 1/(x^2-x-2)

domain

f (x) = \frac{1}{x ^{2} - x - 2}

x < - 1 or - 1 < x < 2 or x > 2

Interval Notation

(- \infty, - 1) \cup (- 1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 1

The function domain

x < - 1 or - 1 < x < 2 or x > 2

y = 2^{\frac{x}{4}}

f (x) = \frac{2}{x ^{2} - 16}

- \frac{5 x}{x - 2}

\frac{2 x ^{2}}{x ^{2} + 2 x - 15}

f (x) = 3 + 4 - x

What is the domain of f(x)= 1/(x^2-x-2) ?
The domain of f(x)= 1/(x^2-x-2) is x<-1\lor-1<x<2\lor x>2