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Popular >

range of cos(2x+5)

Solution

range

cos (2 x + 5)

Solution

- 1 \leq f (x) \leq 1

+1

Solution steps

The range of the basic

cos

function is

- 1 \leq cos (2 x + 5) \leq 1

- 1 \leq cos (2 x + 5) \leq 1

Therefore the range is

- 1 \leq f (x) \leq 1

Popular Examples

asymptotes of (x^2+5x+4)/(x^2+3x+2)asymptotes

\frac{x ^{2} + 5 x + 4}{x ^{2} + 3 x + 2}

intercepts of f(x)=(2x-1)/(x-7)intercepts

f (x) = \frac{2 x - 1}{x - 7}

inflection f(x)=2x^3-3x^2+5x-6 inflection points

f (x) = 2 x^{3} - 3 x^{2} + 5 x - 6

inverse of f(x)=(8-5x)/4 inverse

f (x) = \frac{8 - 5 x}{4}

asymptotes of (2t+3)/(t+4)asymptotes

\frac{2 t + 3}{t + 4}

Frequently Asked Questions (FAQ)

What is the range of cos(2x+5) ?
The range of cos(2x+5) is -1<= f(x)<= 1