What is the domain of 1/(sqrt(x^4+2)+74) ?

The domain of 1/(sqrt(x^4+2)+74) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 1/(sqrt(x^4+2)+74)

domain

\frac{1}{x ^{4} + 2 + 74}

- \infty < x < \infty

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = 3 x^{2} - 5

f (x) = \frac{1}{( x ^{2} - 20 )}

(- 3.1, - 2.8), (- 4.92, - 3.3)

f (x) = 5 x^{4} + 40 x^{3} - x^{2} - 8 x

f (x) = 5 (x + 4)^{2} - 1

What is the domain of 1/(sqrt(x^4+2)+74) ?
The domain of 1/(sqrt(x^4+2)+74) is -infinity <x<infinity