What is the inverse of f(x)= 1/5 x^3-4 ?

The inverse of f(x)= 1/5 x^3-4 is cube root of 5x+20

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inverse of f(x)= 1/5 x^3-4

inverse

f (x) = \frac{1}{5} x^{3} - 4

3 5 x + 20

Solution steps

y = \frac{1}{5} x^{3} - 4

Replace

x

with

y

x = \frac{1}{5} y^{3} - 4

Solve for

y, x = \frac{1}{5} y^{3} - 4

3 5 x + 20

f (x) = - \frac{1}{x ^{2} - 81}

(5, - 5), (7, - 2)

f (x) = 3 x + 5

x

f (t) = - 5 sin (7 t - 1)

What is the inverse of f(x)= 1/5 x^3-4 ?
The inverse of f(x)= 1/5 x^3-4 is cube root of 5x+20