What is the inverse of f(x)=-x^2+4x-2 ?

The inverse of f(x)=-x^2+4x-2 is 2-sqrt(-x+2),sqrt(-x+2)+2

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inverse of f(x)=-x^2+4x-2

inverse

f (x) = - x^{2} + 4 x - 2

2 - - x + 2, - x + 2 + 2

Solution steps

y = - x^{2} + 4 x - 2

Replace

x

with

y

x = - y^{2} + 4 y - 2

Solve for

y, x = - y^{2} + 4 y - 2

2 - - x + 2, - x + 2 + 2

f (x) = 2 + 7 x

f (x) = 4 - x^{2} - y^{2} = 0

\frac{3 x}{x ^{2} + 1}

f (x) = \frac{5}{2} x + 8

f (x) = (x - 1)^{2} + 1

What is the inverse of f(x)=-x^2+4x-2 ?
The inverse of f(x)=-x^2+4x-2 is 2-sqrt(-x+2),sqrt(-x+2)+2