What is the domain of f(x)=sqrt(x+1)-1/x ?

The domain of f(x)=sqrt(x+1)-1/x is -1 0

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domain of f(x)=sqrt(x+1)-1/x

domain

f (x) = x + 1 - \frac{1}{x}

- 1 \leq x < 0 or x > 0

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or x > 0

f (x) = \frac{2}{x} - 1

f (x) = - 9 + 8 x - x^{3}

2 x^{2} - 7 x

x^{3} - 3

\frac{1}{x + 7}

What is the domain of f(x)=sqrt(x+1)-1/x ?
The domain of f(x)=sqrt(x+1)-1/x is -1<= x<0\lor x>0