We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the extreme f(x)=x^3-x^2-8x+12,-2<= x<= 0 ?
- The extreme f(x)=x^3-x^2-8x+12,-2<= x<= 0 is Minimum(-2,16),Maximum(-4/3 , 500/27),Minimum(0,12)