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Frequently Asked Questions (FAQ)
What is the extreme f(x)=3x^3-3x^2-3x+2,-1<= x<= 0 ?
- The extreme f(x)=3x^3-3x^2-3x+2,-1<= x<= 0 is Minimum(-1,-1),Maximum(-1/3 , 23/9),Minimum(0,2)