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Frequently Asked Questions (FAQ)
What is the f(x,y)= 1/5 x^5-5/3 x^3+4x+xy^2 ?
- The f(x,y)= 1/5 x^5-5/3 x^3+4x+xy^2 is Minimum(2,0),Maximum(-2,0),Saddle(1,0),Saddle(-1,0)