What is the domain of f(x)=4+sqrt(5+x) ?

The domain of f(x)=4+sqrt(5+x) is x>=-5

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domain of f(x)=4+sqrt(5+x)

domain

f (x) = 4 + 5 + x

x \geq - 5

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 5

The function domain

x \geq - 5

\frac{1}{3 x ^{2} - 3 x - 6}

f (x) = \frac{x ^{2} - 3 x - 10}{x ^{2} - 7 x - 18}

f (x) = (- 1.3) (0.2) (1.1)

\frac{x + 5}{x ( x + 7 )}

x - 2 x + 3

What is the domain of f(x)=4+sqrt(5+x) ?
The domain of f(x)=4+sqrt(5+x) is x>=-5